document.write( "Question 1146195: The lengths of the sides of a right angles triangle form the terms of an
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document.write( "arithmetic sequence. If the hypotenuse is 15cm in length, what is the length of
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document.write( "the other two sides? \n" );
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Algebra.Com's Answer #767483 by Edwin McCravy(20060)![]() ![]() You can put this solution on YOUR website! The sides can be represented by a-d, a, a+d where a+d = the hypotenuse = 15 cm\r\n" ); document.write( "\r\n" ); document.write( "So the first equation comes from that:\r\n" ); document.write( "\r\n" ); document.write( "a+d = 15\r\n" ); document.write( "\r\n" ); document.write( "The second equation comes from the Pythagorean theorem:\r\n" ); document.write( "\r\n" ); document.write( "(a-d)² + a² = (a+d)²\r\n" ); document.write( "\r\n" ); document.write( " a² = (a+d)² - (a-d)²\r\n" ); document.write( "\r\n" ); document.write( " a² = [(a+d)-(a-d)][(a+d)+(a-d)]\r\n" ); document.write( " \r\n" ); document.write( " a² = [a+d-a+d][a+d+a-d]\r\n" ); document.write( "\r\n" ); document.write( " a² = [2d][2a]\r\n" ); document.write( "\r\n" ); document.write( " a² = 4ad\r\n" ); document.write( "\r\n" ); document.write( " a² - 4ad = 0\r\n" ); document.write( "\r\n" ); document.write( " a(a - 4d) = 0\r\n" ); document.write( "\r\n" ); document.write( "a = 0; a - 4d = 0\r\n" ); document.write( "\r\n" ); document.write( " a = 4d \r\n" ); document.write( "\r\n" ); document.write( "For a = 0, \r\n" ); document.write( "not possible because\r\n" ); document.write( "sides of a triangle are\r\n" ); document.write( "positive numbers. For a = 4d\r\n" ); document.write( "\r\n" ); document.write( " a+d = 15\r\n" ); document.write( " \r\n" ); document.write( " 4d+d = 15 \r\n" ); document.write( "\r\n" ); document.write( " 5d = 15\r\n" ); document.write( "\r\n" ); document.write( " d = 3\r\n" ); document.write( " \r\n" ); document.write( " a = 4(3)\r\n" ); document.write( "\r\n" ); document.write( " a = 12\r\n" ); document.write( "\r\n" ); document.write( "The sides are \r\n" ); document.write( "\r\n" ); document.write( "a-d = 12-3 = 9\r\n" ); document.write( " a = 12\r\n" ); document.write( "a+d = 12+3 = 15 (given) 9, 12, 15\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |