document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1146173>Question 1146173</A>: <I><SPAN STYLE=\"word-break: break-all;\"> When a child emptied her coin bank, she had a collection of pennies, nickels, and dimes. There were a total of 50 pennies, and a combined total of 30 nickels and dimes. If the coins had a total value of 250 cents, how many nickels and dimes were in the bank?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #767444 by </B><A HREF=/tutors/aboutme.mpl?userid=math_helper><B>math_helper(2461)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=math_helper><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=math_helper><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=767444\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
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document.write( "The starting point is to immediately subtract the 50 pennies to arrive at 200 cents worth of nickels and dimes.   \r<BR>\n" );
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document.write( " N = number of nickels<BR>\n" );
document.write( " 30-N = number of dimes\r<BR>\n" );
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document.write( "5N + 10(30-N) = 200<BR>\n" );
document.write( "-5N + 300 = 200<BR>\n" );
document.write( "   5N = 100<BR>\n" );
document.write( "    N = 20   nickels  -->  and (30-20) = 10 dimes\r<BR>\n" );
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document.write( "Check:  5*20 + 10*10 = 100 + 100 = 200 cents (that plus the original 50 pennies gets you to 250 cents in the coin bank).\r<BR>\n" );
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document.write( "Some tutors will show you other ways to solve it.  Those are probably fine methods, I just prefer the mechanical method above.<BR>\n" );
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