document.write( "Question 1145993: A computer retail store has 9 personal computers in stock. A buyer wants to purchase 4 of them. Unknown to either the retail store or the buyer, 4 of the computers in stock have defective hard drives. Assume that the computers are selected at random.\r
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\n" ); document.write( "\n" ); document.write( "(b) What is the probability that exactly one of the computers will be defective?\r
\n" ); document.write( "\n" ); document.write( "(c) What is the probability that at least one of the computers selected is defective?
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Algebra.Com's Answer #767369 by VFBundy(438)\"\" \"About 
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(a) In how many different ways can the 4 computers be chosen?
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\n" ); document.write( "9C4 = \"9%21%2F%284%21%2A5%21%29\" = 126
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\n" ); document.write( "Since 4 out of the 9 computers are defective, this means there is a 0.4444 probability a randomly chosen computer is defective. (You will need to know this to answer the next two questions.)
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\n" ); document.write( "(b) What is the probability that exactly one of the computers will be defective?
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\n" ); document.write( "\"%280.4444%29%5E1+%2A+%280.5556%29%5E3+%2A+%284%21%2F%281%21%2A3%21%29%29\" = 0.4444 * 0.1715 * 4 = 0.3049
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\n" ); document.write( "(c) What is the probability that at least one of the computers selected is defective?
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\n" ); document.write( "To do this, you compute the probability that NONE of the four computers is defective, then subtract this result from 1:
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\n" ); document.write( "\"1+-+%280.5556%29%5E4\" = 1 - 0.0953 = 0.9047
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