document.write( "Question 1146037: A rectangular piece of cardboard is 12 in. longer than it is wide. Squares 3 in. on a side are to be cut from each corner, and then the sides will be folded up to make an open box with a volume of 135 in3. Find the length and width of the piece of cardboard. \n" ); document.write( "
Algebra.Com's Answer #767308 by greenestamps(13203)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The volume of the box is length times width times height. The height is 3 inches, and the volume is 135 cubic inches. So the length times the width is 135/3 = 45. \n" ); document.write( "When the 3-inch square pieces are cut out of each corner, the new length is still 12 inches more than the new width. \n" ); document.write( "So we can solve the problem simply by finding two numbers that differ by 12 and whose product is 45. \n" ); document.write( "A bit of mental arithmetic shows those two numbers to be 3 and 15. Then, since 3-inch square pieces were cut out of each corner of the piece of cardboard, the dimensions of the piece of cardboard were 3+6=9 and 15+6=21. \n" ); document.write( "ANSWER: The piece of cardboard was 21x9 inches. \n" ); document.write( "You can, of course, solve the problem using formal algebra. \n" ); document.write( "x = width \n" ); document.write( "x+12 = length \n" ); document.write( "The volume is 135 after cutting out 3-inch squares from each corner: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "ANSWER: \n" ); document.write( "width = x = 9 \n" ); document.write( "length = x+12 = 21 \n" ); document.write( " |