document.write( "Question 1145938: A hammer was dropped from a Carpenter's pocket from a height of 300 ft building and falls towards the earth in a straight line.
\n" ); document.write( "a)What is the average velocity during the time it is falling.
\n" ); document.write( "b)What is the instantaneous velocity of the hammer when it hit the ground? \n" ); document.write( "

Algebra.Com's Answer #767234 by ikleyn(52786) $\"\"$ $\"About$

You can put this solution on YOUR website!
.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " The solution by tutor @rothauserc is not precisely correct, therefore I came to bring corrected solution.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "

\r\n" );
document.write( "Since the height of the building is given in feet, we will use 32 feet per second squared as the acceleration of gravity\r\n" );
document.write( "\r\n" );
document.write( "distance(s) = 0.5 * at^2, where a is acceleration of gravity and t is the time it takes for the hammer to hit the ground\r\n" );
document.write( "\r\n" );
document.write( "0.5 * 32 * t^2 = 300\r\n" );
document.write( "\r\n" );
document.write( "t^2 = 300/16 = 18.75\r\n" );
document.write( "\r\n" );
document.write( "t = 4.33 seconds\r\n" );
document.write( "\r\n" );
document.write( "(a) average velocity(v) =  =  =  69.28 feet/sec  <<<---===  my correction is in this line\r\n" );
document.write( "\r\n" );
document.write( "(b) instantaneous velocity = at = 32 * 4.33 = 138.56 feet/sec\r\n" );
document.write( "

\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );