document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1145938>Question 1145938</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A hammer was dropped from a Carpenter's pocket from a height of 300 ft building and falls towards the earth in a straight line.<BR>\n" );
document.write( "a)What is the average velocity during the time it is falling.<BR>\n" );
document.write( "b)What is the instantaneous velocity of the hammer when it hit the ground? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #767233 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=767233\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since the height of the building is given in feet, we will use 32 feet per second squared as the acceleration of gravity<BR>\n" );
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document.write( "distance(s) = 0.5 * at^2, where a is acceleration of gravity and t is the time it takes for the hammer to hit the ground<BR>\n" );
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document.write( "0.5 * 32 * t^2 = 300<BR>\n" );
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document.write( "t^2 = 300/16 = 18.75<BR>\n" );
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document.write( "t = 4.33 seconds<BR>\n" );
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document.write( "(a) average velocity(v) = a/t = 32/4.33 =  7.39 feet/sec<BR>\n" );
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document.write( "(b) instantaneous velocity = at = 32 * 4.33 = 138.56 feet/sec<BR>\n" );
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