document.write( "Question 105369: This is in inequalities, I don't know how to start this
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document.write( " At Burger Brothers the price of a hamburger is twice the price of an order of french fries and the price of a coke is $0.40 more than the price of the fries. Burger Brothers advertises that you get a complete meal, burger, fries and a coke for under $4.00 What is the price range of a order of fries?\r
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document.write( " Thanks for any help settting on my way. \n" );
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Algebra.Com's Answer #76716 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! Start by letting H = the price of a hamburger, F = the price of french fries, and C = the price of a Coca Cola. \n" ); document.write( "From the problem description, you can write: \n" ); document.write( "H = 2F \"The price of a hamburger (H) is (=) twice the price of french fries (2F)\" \n" ); document.write( "C = F+$0.40 \"The price of a Coca Cola (C) is (=) 40 cents more than the price of french fries (F+$0.40)\" \n" ); document.write( "Now the sum of these three items can be had for less than $4.00 (<$4.00), so we can write the inequality: \n" ); document.write( "H+F+C < $4.00 Now we substitute H = 2F and C = F+$0.40 to get: \n" ); document.write( "2F+F+F+$0.40 < $4.00 Combining like-terms, we get: \n" ); document.write( "4F+$0.40 < $4.00 Subtracting $0.40 from both sides of the inequality, we have: \n" ); document.write( "4F < $3.60 Dividing both sides by 4, we end up with: \n" ); document.write( "F < $0.90 or, in words, the price of french fries is no more than $0.90 \n" ); document.write( " |