document.write( "Question 105358: I am having a hard time with sovling the following problem. I need to solve the following system by addition.\r
\n" ); document.write( "\n" ); document.write( "2x-y=1 and -2x+3y=5\r
\n" ); document.write( "\n" ); document.write( "I have done the following:
\n" ); document.write( "2x-y=1
\n" ); document.write( "-2x+3y=5
\n" ); document.write( "-y=1
\n" ); document.write( "3y=5
\n" ); document.write( "2y/2=-4/2
\n" ); document.write( "y=-2
\n" ); document.write( "Now I dont understand how to solve for the x. And did I solve for the y correctly?
\n" ); document.write( "

Algebra.Com's Answer #76715 by checkley75(3666)\"\" \"About 
You can put this solution on YOUR website!
2X-Y=1
\n" ); document.write( "-2X+3Y=5
\n" ); document.write( "----------------------- NOW ADD
\n" ); document.write( "-Y+3Y=1+5
\n" ); document.write( "2Y=6
\n" ); document.write( "Y=6/2
\n" ); document.write( "Y=3 ANSWER.
\n" ); document.write( "NOW SUBSTITUTE 2 FOR Y & SOLVE FOR X
\n" ); document.write( "-2X+3*3=5
\n" ); document.write( "-2X+9=5
\n" ); document.write( "-2X=5-9
\n" ); document.write( "-2X=-4
\n" ); document.write( "X=-4/-2
\n" ); document.write( "X=2 ANSWER.
\n" ); document.write( "PROOF
\n" ); document.write( "2*2-3=1
\n" ); document.write( "4-3=1
\n" ); document.write( "1=1
\n" ); document.write( "
\n" );