document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1145856>Question 1145856</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I would appreciate if someone could help me on this problem-please if you could show the work so I can understand it.  Thanks\r<BR>\n" );
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document.write( "A pirate sails in a circular route around point A,<BR>\n" );
document.write( "as shown to the right, with a circumference of<BR>\n" );
document.write( "32 km, and a merchant ship sails in a circular<BR>\n" );
document.write( "route around point B with a circumference of 48 km.<BR>\n" );
document.write( "If they both start where the routes meet, and the pirate<BR>\n" );
document.write( "sails 12 km per day and the merchant sails at 8 km per<BR>\n" );
document.write( "day, what is the least number of days later they will<BR>\n" );
document.write( "next meet?\r<BR>\n" );
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document.write( "CHOICE ANSWERS GIVEN BELOW:<BR>\n" );
document.write( "A) 8 days B) 16 days C) 24 days D) 32 days </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #767128 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13208)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=767128\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "The pirate ship makes one complete circle every 32/12 = 8/3 days.<br><BR>\n" );
document.write( "The merchant ship makes one complete circle every 48/8 = 6 days.<br><BR>\n" );
document.write( "The number of days until they are again at the same point is the least common multiple of 8/3 and 6.<br><BR>\n" );
document.write( "It's a bit unusual to need to find the LCM of two numbers where one of them is a fraction.  So let me show the way I prefer for finding the least common multiple of ANY two numbers.<br><BR>\n" );
document.write( "(1) Make a fraction with the two numbers as the numerator and denominator:<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%288%2F3%29%2F6 ALIGN=MIDDLE  ALT=\"%288%2F3%29%2F6\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "(2) Simplify the fraction to where the numerator and denominator are whole numbers with no common factor:<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%288%2F3%29%2F6+=+8%2F18+=+4%2F9 ALIGN=MIDDLE  ALT=\"%288%2F3%29%2F6+=+8%2F18+=+4%2F9\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "(3) Write the equation that says the original fraction and the simplified fractions are equivalent:<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%288%2F3%29%2F6+=+4%2F9 ALIGN=MIDDLE  ALT=\"%288%2F3%29%2F6+=+4%2F9\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "(4) Cross multiplying in either direction will give you the LCM:<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%288%2F3%29%2A9+=+8%2A3+=+24 ALIGN=MIDDLE  ALT=\"%288%2F3%29%2A9+=+8%2A3+=+24\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6%2A4+=+24 ALIGN=MIDDLE  ALT=\"6%2A4+=+24\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "So the least common multiple of 8/3 and 6 is 24.<br><BR>\n" );
document.write( "ANSWER C: 24 days </SPAN>\n" );
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