document.write( "Question 105362: 3r+1<4r+7 \n" ); document.write( "
Algebra.Com's Answer #76711 by checkley75(3666)\"\" \"About 
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3R+1<4R+7
\n" ); document.write( "3R-4R<7-1
\n" ); document.write( "-R<6 DIVIDE BOTH SIDES BY -1 WHICH CHANGES THE < TO A >.
\n" ); document.write( "R>-6
\n" ); document.write( "PROOF
\n" ); document.write( "LET R=-5
\n" ); document.write( "3*-5+1<4*-5+7
\n" ); document.write( "-15+1<-20+7
\n" ); document.write( "-14<-13
\n" ); document.write( "
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