document.write( "Question 1145776: A company prices its tornado insurance using the following assumptions:
\n" ); document.write( "• In any calendar year, there can be at most one tornado.
\n" ); document.write( "• In any calendar year, the probability of a tornado is 0.12.
\n" ); document.write( "• The number of tornadoes in any calendar year is independent of the number of tornados in any other calendar year.
\n" ); document.write( "Using the company's assumptions, calculate the probability that there are fewer than 4 tornadoes in a 17-year period.
\n" ); document.write( "

Algebra.Com's Answer #767068 by VFBundy(438)\"\" \"About 
You can put this solution on YOUR website!
\"Fewer than 4 tornadoes\" is another way of saying 3,2,1, or 0 tornadoes.
\n" ); document.write( "
\n" ); document.write( "Probability of exactly 3 tornadoes: \"%280.12%29%5E3%2A%280.88%29%5E14%2A%2817%21%2F%283%21%2A14%21%29%29\" = 0.1963
\n" ); document.write( "Probability of exactly 2 tornadoes: \"%280.12%29%5E2%2A%280.88%29%5E15%2A%2817%21%2F%282%21%2A15%21%29%29\" = 0.2878
\n" ); document.write( "Probability of exactly 1 tornado: \"%280.12%29%5E1%2A%280.88%29%5E16%2A%2817%21%2F%281%21%2A16%21%29%29\" = 0.2638
\n" ); document.write( "Probability of exactly 0 tornadoes: \"%280.88%29%5E17\" = 0.1138
\n" ); document.write( "
\n" ); document.write( "Probability of \"fewer than 4 tornadoes\": 0.1963 + 0.2878 + 0.2638 + 0.1138 = 0.8617
\n" ); document.write( "
\n" );