document.write( "Question 1145798: It's 207.5 miles from Amberwood to Bravotown. It's another 220 miles from Bravotown to C-town. Ethan drives 30 miles faster from Bravotown to C-town than from Amberwood to Bravotown. If his combined travel time is 12.3 hours, what are his average speeds?\r
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Algebra.Com's Answer #767054 by ikleyn(52787)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Let x be the average rate from A to B, in miles per hour. \r\n" );
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document.write( "Then the average rate from B to C is  (x+30) mph.\r\n" );
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document.write( "The traveling time from A to B is  \"207.5%2Fx\" hours;\r\n" );
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document.write( "The traveling time from B to C is  \"220%2F%28x%2B30%29\" hours.\r\n" );
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document.write( "The total time is 12.3 hours, which gives you an equation\r\n" );
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document.write( "    \"207.5%2Fx\" + \"220%2F%28x%2B30%29\"  = 12.3  hours.\r\n" );
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document.write( "It is the \"time\" equation, and as soon as you get it, the setup is just completed.\r\n" );
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document.write( "To solve the equation, multiply both sides by x*(x+30)*10.  You will get\r\n" );
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document.write( "    2075*(x+30) + 2200*x = 123x*(x+1)\r\n" );
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document.write( "Simplify this quadratic equation and write it in the standard form\r\n" );
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document.write( "Then solve it and find its positive root.\r\n" );
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document.write( "It will be the answer for the average speed from A to B.\r\n" );
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document.write( "The average speed from B to C is 30 mph greater.\r\n" );
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