document.write( "Question 1145794: A, B and C can do a piece of work in 10 days. A and B can do it in 12 days, and A and C in 20 days. How many days would it take each to do the work place? \n" ); document.write( "
Algebra.Com's Answer #767052 by VFBundy(438)![]() ![]() You can put this solution on YOUR website! Rate of work for A = 1/A job per day \n" ); document.write( "Rate of work for B = 1/B job per day \n" ); document.write( "Rate of work for C = 1/C job per day \n" ); document.write( " \n" ); document.write( "Rate of work for A, B, and C working together = 1/A + 1/B + 1/C = 1/10 \n" ); document.write( "Rate of work for A and B working together = 1/A + 1/B = 1/12 \n" ); document.write( "Rate of work for A and C working together = 1/A + 1/C = 1/20 \n" ); document.write( " \n" ); document.write( "1/A + 1/C = 1/20 \n" ); document.write( "1/C = 1/20 - 1/A \n" ); document.write( " \n" ); document.write( "1/A + 1/B = 1/12 \n" ); document.write( "1/B = 1/12 - 1/A \n" ); document.write( " \n" ); document.write( "1/A + 1/B + 1/C = 1/10 \n" ); document.write( "1/A = 1/10 - 1/C - 1/B \n" ); document.write( "1/A = 1/10 - (1/20 - 1/A) - (1/12 - 1/A) \n" ); document.write( "1/A = 1/10 - 1/20 + 1/A - 1/12 + 1/A \n" ); document.write( "1/A = -1/30 + 2/A \n" ); document.write( "-1/A = -1/30 \n" ); document.write( "1/A = 1/30 \n" ); document.write( "A = 30 \n" ); document.write( "It takes 'A' 30 days to do the job alone. \n" ); document.write( " \n" ); document.write( "1/A + 1/B = 1/12 \n" ); document.write( "1/30 + 1/B = 1/12 \n" ); document.write( "1/B = 1/12 - 1/30 \n" ); document.write( "1/B = 1/20 \n" ); document.write( "B = 20 \n" ); document.write( "It takes 'B' 20 days to do the job alone. \n" ); document.write( " \n" ); document.write( "1/A + 1/C = 1/20 \n" ); document.write( "1/30 + 1/C = 1/20 \n" ); document.write( "1/C = 1/20 - 1/30 \n" ); document.write( "1/C = 1/60 \n" ); document.write( "C = 60 \n" ); document.write( "It takes 'C' 60 days to do the job alone. \n" ); document.write( " |