document.write( "Question 1145689: Listed below are the amounts of time (in months) that the employees of a restaurant have been working at the restaurant. Find the standard deviation of the data set, rounding to one more decimal place than is present in the data.\r
\n" ); document.write( "\n" ); document.write( "2 3 5 13 22 35 60 86 101 122 \n" ); document.write( "
Algebra.Com's Answer #767027 by VFBundy(438)\"\" \"About 
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Calculate the mean of the set = \"%282+%2B+3+%2B+5+%2B+13+%2B+22+%2B+35+%2B+60+%2B+86+%2B+101+%2B+122%29%2F10\" = 44.9
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\n" ); document.write( "Subtract the mean from each data point:
\n" ); document.write( "2 - 44.9 = -42.9
\n" ); document.write( "3 - 44.9 = -41.9
\n" ); document.write( "5 - 44.9 = -39.9
\n" ); document.write( "13 - 44.9 = -31.9
\n" ); document.write( "22 - 44.9 = -22.9
\n" ); document.write( "35 - 44.9 = -9.9
\n" ); document.write( "60 - 44.9 = 15.1
\n" ); document.write( "86 - 44.9 = 41.1
\n" ); document.write( "101 - 44.9 = 56.1
\n" ); document.write( "122 - 44.9 = 77.1
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\n" ); document.write( "Square each result:
\n" ); document.write( "(-42.9)² = 1840.41
\n" ); document.write( "(-41.9)² = 1755.61
\n" ); document.write( "(-39.9)² = 1592.01
\n" ); document.write( "(-31.9)² = 1017.61
\n" ); document.write( "(-22.9)² = 524.41
\n" ); document.write( "(-9.9)² = 98.01
\n" ); document.write( "(15.1)² = 228.01
\n" ); document.write( "(41.1)² = 1689.21
\n" ); document.write( "(56.1)² = 3147.21
\n" ); document.write( "(77.1)² = 5944.41
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\n" ); document.write( "Find the sum of the squared values:
\n" ); document.write( "1840.41 + 1755.61 + 1592.01 + 1017.61 + 524.41 + 98.01 + 228.01 + 1689.21 + 3147.21 + 5944.41 = 17839.90
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\n" ); document.write( "Because the data set is the entire population, divide the sum of the squared values by the number of data in the set*:
\n" ); document.write( "17839.90/10 = 1783.990
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\n" ); document.write( "*(NOTE: If the data set were from a sample, and not the entire population, you would have divided by the number of data in the set minus 1.)
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\n" ); document.write( "This is your variance: 1783.990. To find the standard deviation, take the square root of the variance...which is 42.2. \n" ); document.write( "
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