document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1145711>Question 1145711</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Based on the function<BR>\n" );
document.write( "y=f(x)=1,822.8×(1.4^x)\r<BR>\n" );
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document.write( "What would be the predicted transistor count for the years 2006 and 2017? x is the number of years after 1971, so for 1971, x = 0. \r<BR>\n" );
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document.write( "The Transistor Count for 2006<BR>\n" );
document.write( "Round off the final answer to the nearest whole value.	\r<BR>\n" );
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document.write( "Transistor Count for 2017<BR>\n" );
document.write( "Round off the final answer to the nearest whole value.	<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #766949 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=766949\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the function is y = 1,822.8 * 1.4^x<BR>\n" );
document.write( "x is the number of years after 1971,<BR>\n" );
document.write( "for 1971, x = 0<BR>\n" );
document.write( "for 2006, x = 2006 - 1971 = 35<BR>\n" );
document.write( "for 2017, x = 2017 - 1971 = 46<BR>\n" );
document.write( "for 2006, y = 1,822.8 * 1.4 ^ 35 = 237,257,674.1<BR>\n" );
document.write( "for 2017, x = 1,822.8 * 1.4 ^ 46 = 9, 607,904,134.0<BR>\n" );
document.write( "those are your solutions.\r<BR>\n" );
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