document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1145716>Question 1145716</A>: <I><SPAN STYLE=\"word-break: break-all;\"> x/2 + y/3=7/6\r<BR>\n" );
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document.write( "2x/3+3y/4=5/4\r<BR>\n" );
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document.write( "Is there something I can do here so I can get rid of the fractions?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #766941 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=766941\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (1) x/2 +y/3 = 7/6<BR>\n" );
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document.write( "(2) 2x/3 +3y/4 = 5/4<BR>\n" );
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document.write( "In each equation, multiply both sides of the = by the least common multiple(lcm)<BR>\n" );
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document.write( "For equation (1), the lcm is 6, therefore equation 1 becomes<BR>\n" );
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document.write( "3x +2y = 7<BR>\n" );
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document.write( "Foe equation (2), the lcm is 12, therefore equation 2 becomes<BR>\n" );
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document.write( "8x +9y = 15<BR>\n" );
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