document.write( "Question 1145662: Aaron and Jonathan take turns shooting a free throw, with Aaron going first. Whoever makes the first shot wins. The game continues until
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document.write( "someone makes the shot. Aaron has a 40% chance of making a free throw, while Jonathan has a 50% chance. What is Aaron’s chance of
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document.write( "winning the game? \n" );
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Algebra.Com's Answer #766908 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "P(Aaron wins on his first shot) = 40% = 2/5 \n" ); document.write( "P(Aaron wins on his second shot) = (3/5)*(1/2)*(2/5) = 3/25 \n" ); document.write( "(Aaron misses on his first, probability 3/5; then Jonathan misses on his first, probability 1/2; then Aaron makes his second shot probability 2/5) \n" ); document.write( "P(Aaron wins on his third shot) = (3/5)*(1/2)*(3/5)*(1/2)*(2/5) = 9/250 \n" ); document.write( "etc., etc., etc..... \n" ); document.write( "The sum of the probabilities is a geometric progression with first term 2/5 and common ratio (3/5)*(1/2) = 3/10. \n" ); document.write( "The probability that Aaron wins is the sum of that infinite geometric progression: \n" ); document.write( " |