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document.write( "1.Mix a solution that is 30% alcohol with a solution that is 80% alcohol to make 725 mL of a solution that is 60% alcohol. How much (in mL) of each solution should you use?
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document.write( "30% alcohol solution__ml
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document.write( "80% alcohol solution__ml.\r
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document.write( "2.A welder has 15 pieces of 4 ft steel angle and 18 pieces of 2 ft steel angle. What is the ratio of pieces of 4 ft steel angle to 2 ft steel angle? (Enter your answer in fraction form.) \n" );
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Algebra.Com's Answer #766899 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "First a standard algebraic solution to the mixture problem.... \n" ); document.write( "x = mL of 30% alcohol solution \n" ); document.write( "725-x = mL of 80% alcohol solution \n" ); document.write( ".30(x) = amount of alcohol in x mL of 30% solution \n" ); document.write( ".80(725-x) = amount of alcohol in (725-x mL of 80% solution \n" ); document.write( ".60(725 = amount of alcohol in 725 mL of 60% solution \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "ANSWER: 290 mL of the 30% solution and 725-290 = 435 mL of the 80% solution. \n" ); document.write( "That's a perfectly good method for solving mixture problems like this. \n" ); document.write( "But there is a much easier way.... \n" ); document.write( "Now a much easier solution, based on where the 60% lies between the 30% and 80%.... \n" ); document.write( "(1) 60 is 3/5 of the way from 30 to 80 (look at the 3 numbers 30, 60, and 80 on a number line; 30 to 60 is 30; 30 to 80 is 50; 30/50 = 3/5) \n" ); document.write( "(2) Therefore, 3/5 of the mixture should be the higher percentage solution. \n" ); document.write( "ANSWER: 3/5 of 725 mL, or 435 mL, of 80% alcohol solution; 2/5 of 725 mL, or 290 mL, of 30% alcohol solution \n" ); document.write( " \n" ); document.write( " |