document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1145439>Question 1145439</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If x² + x = 1, Then find (x^5  + 8)/(x + 1) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #766895 by </B><A HREF=/tutors/aboutme.mpl?userid=thmei1><B>thmei1(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=thmei1><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=766895\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x² + x = 1 , is the same as x² + x - 1 = 0, it is a quadratic so you can solve for x using the quadratic formula <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ ALIGN=MIDDLE  ALT=\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "a = 1, b = 1, c = -1<BR>\n" );
document.write( "which will end up being<BR>\n" );
document.write( "x = - (1 +- sqrt(5)) / 2\r<BR>\n" );
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document.write( "+- results in two answers\r<BR>\n" );
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document.write( "substitute - (1 + sqrt(5)) / 2 into x in the problem (x^5  + 8) / (x + 1) = 5<BR>\n" );
document.write( "substitute - (1 - sqrt(5)) / 2 into x in the problem (x^5  + 8) / (x + 1) = 5\r<BR>\n" );
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document.write( "in this case if you plug in the two different x given by the quadratic formula you only end up with x = 5 \r<BR>\n" );
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document.write( "Answer : x = 5  </SPAN>\n" );
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