document.write( "Question 1145654: 1.1 A fair die is rolled twice. Find the probability of the following events:
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\n" ); document.write( "3. 1.2 Two distinct diceAand Barerolled. Whatis the probabilityofeachofthe following events?
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\n" ); document.write( " c. The sum of the face values is 7
\n" ); document.write( "d. One of the values is 3 and the sum of the two values is 5
\n" ); document.write( "e. One of the values is 3 or the sum of the two values is 5
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Algebra.Com's Answer #766887 by ikleyn(52847)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "            One and only one problem per post.\r
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document.write( "(a)  In all, there are 6*6 = 36 possible outcomes, with equal probability \"%281%2F6%29%2A%281%2F6%29\" = \"1%2F36\" each.\r\n" );
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document.write( "     The favorable outcomes are (1,2), (2,4), and (3,6). In all, there are 3 favorable outcomes.\r\n" );
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document.write( "      Therefore, the answer is  \"3%2F36\" = \"1%2F12\".   \r\n" );
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document.write( "(b)  The favorable outcomes are (1,1), \r\n" );
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document.write( "                                (2,1), (2,2)\r\n" );
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document.write( "                                (3,1), (3,2), (3,3)\r\n" );
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document.write( "                                . . . . . . . . . . . . \r\n" );
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document.write( "                                (6,1), (6,2), (6,3), (6,4), (6,5), (6,6)\r\n" );
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document.write( "     In all, there are  \"%286%2A5%29%2F2\" + 6 = 15 + 6 = 21 favorable outcomes.\r\n" );
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document.write( "     Therefore, the answer in this case is  \"21%2F36\" = \"7%2F12\".\r\n" );
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document.write( "(c)  What your \"c\" means, is totally unclear.\r\n" );
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\n" ); document.write( "\n" ); document.write( "If you want to learn this subject,  look into the lesson\r
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\n" ); document.write( "\n" ); document.write( "After reading it,  you will become an expert in the area.\r
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