document.write( "Question 1145660: Find the dimensions of a rectangle whose area is 156 cm2 and whose perimeter is 50 cm. \n" ); document.write( "
Algebra.Com's Answer #766884 by ikleyn(52788)\"\" \"About 
You can put this solution on YOUR website!
.
\n" ); document.write( "
\r\n" );
document.write( "x + y = 50/2\r\n" );
document.write( "\r\n" );
document.write( "xy    = 156\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "==============>\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "x + y = 25\r\n" );
document.write( "\r\n" );
document.write( "xy    = 156\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "==============>\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "x = 25 - y\r\n" );
document.write( "\r\n" );
document.write( "y*(25-y) = 156\r\n" );
document.write( "\r\n" );
document.write( "y^2 - 25y + 156 = 0\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\"y%5B1%2C2%5D\" = \"%2825+%2B-+sqrt%2825%5E2+-+4%2A156%29%29%2F2\" = \"%2825+%2B-+sqrt%281%29%29%2F2\" = \"%2825+%2B-+1%29%2F2\".\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "There are 2 roots,  y= 13  and  y= 12.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "ANSWER.  The dimensions of a rectangle are 12 cm and 13 cm.\r\n" );
document.write( "
\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );