document.write( "Question 1145650: Find the shortest distance from the origin to the graph of the circle with equation given below.\r
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\n" ); document.write( "\n" ); document.write( "x^2−12x+y^2−12y+36=0
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Algebra.Com's Answer #766873 by Alan3354(69443)\"\" \"About 
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Find the shortest distance from the origin to the graph of the circle with equation given below.\r
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\n" ); document.write( "\n" ); document.write( "x^2−12x+y^2−12y+36=0
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\n" ); document.write( "Find the center of the circle and its radius.
\n" ); document.write( "x^2−12x+y^2−12y+36=0
\n" ); document.write( "x^2−12x+y^2−12y = -36
\n" ); document.write( "(x-6)^2 + (y-6)^2 = -36 + 36 + 36 = 36
\n" ); document.write( "The center is (6,6) and the radius is 6.
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\n" ); document.write( "Find the distance d to the center.
\n" ); document.write( "\"d+=+sqrt%286%5E2+%2B+6%5E2%29+=+6sqrt%282%29\"
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\n" ); document.write( "Subtract the radius if d is > radius.
\n" ); document.write( "Distance = \"6sqrt%282%29+-+6\"
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