document.write( "Question 1145650: Find the shortest distance from the origin to the graph of the circle with equation given below.\r
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document.write( "x^2−12x+y^2−12y+36=0 \n" );
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Algebra.Com's Answer #766873 by Alan3354(69443) You can put this solution on YOUR website! Find the shortest distance from the origin to the graph of the circle with equation given below.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^2−12x+y^2−12y+36=0 \n" ); document.write( "----------- \n" ); document.write( "Find the center of the circle and its radius. \n" ); document.write( "x^2−12x+y^2−12y+36=0 \n" ); document.write( "x^2−12x+y^2−12y = -36 \n" ); document.write( "(x-6)^2 + (y-6)^2 = -36 + 36 + 36 = 36 \n" ); document.write( "The center is (6,6) and the radius is 6. \n" ); document.write( "------ \n" ); document.write( "Find the distance d to the center. \n" ); document.write( " \n" ); document.write( "---------- \n" ); document.write( "Subtract the radius if d is > radius. \n" ); document.write( "Distance = \n" ); document.write( " \n" ); document.write( " |