document.write( "Question 1145615: A cyclist sets out on a 3-day trip at an average speed of 15 kph. Six hours later, his wife finds his first aid kit in their dining room table. If she heads after him in the car at 45 kph, how long will it be before she catches him? \n" ); document.write( "

Algebra.Com's Answer #766842 by VFBundy(438) $\"\"$ $\"About$

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Cyclist:
\n" ); document.write( "d = rt = 15(6 + x) = 90 + 15x
\n" ); document.write( "r = 15
\n" ); document.write( "t = 6 + x
\n" ); document.write( "
\n" ); document.write( "Wife:
\n" ); document.write( "d = rt = 45x
\n" ); document.write( "r = 45
\n" ); document.write( "t = x
\n" ); document.write( "
\n" ); document.write( "Distance (cyclist) = Distance (wife)
\n" ); document.write( "
\n" ); document.write( "90 + 15x = 45x
\n" ); document.write( "
\n" ); document.write( "90 = 30x
\n" ); document.write( "
\n" ); document.write( "x = 3
\n" ); document.write( "
\n" ); document.write( "It will take the wife 3 hours (from when she leaves in her car) to catch the cyclist.(This will be nine hours after the cyclist initially set out on his trip.) \n" ); document.write( "

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