document.write( "Question 1145610: I have no done math in years. I am seeking out help for a friend. What is the rule to an equation where the x has an exponent? For example, x^3/4=6 with 3/4 being the exponent? \n" ); document.write( "
Algebra.Com's Answer #766836 by Theo(13342)\"\" \"About 
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x^(3/4) = 6 can be solved as follows:\r
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\n" ); document.write( "\n" ); document.write( "raise both sides of the equation to the power of (4/3) to get:
\n" ); document.write( "x^(3/4)^(4/3) = 6^(4/3)
\n" ); document.write( "this is equivalent to:
\n" ); document.write( "x^(3/4 * 4/3) = 6^(4/3)
\n" ); document.write( "simplify to get x= 6^(4/3) = 10.90272356
\n" ); document.write( "confirm by replacing x with that to get:
\n" ); document.write( "10.90272356^(3/4) = 6
\n" ); document.write( "result is 6 = 6, confirming the solution is correct.\r
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\n" ); document.write( "\n" ); document.write( "x^(3/4) is the same as the fourth foot of x^3 and is also the same as the fourth root of x raised to the third power.\r
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\n" ); document.write( "\n" ); document.write( "this looks like (x^3)^(1/4) or (x^(1/4))^3\r
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\n" ); document.write( "\n" ); document.write( "the basic rule for exponent arithmatic is:\r
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\n" ); document.write( "\n" ); document.write( "(x^a)^b = x^(a*b)
\n" ); document.write( "if a is 3 and b is (1/4), you get (x^3)^(1/4) = x^(3*1/4) = x^(3/4)
\n" ); document.write( "if a is 1/4 and b is 3, you get (x^(1/4)^3 = x^((1/4)*3) = x^(3/4)\r
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