document.write( "Question 1145525: Find three consecutive negative integers such that the sum of the greatest and twice the smallest is equal to four times the middle integer. So far 4(n-1)=n+2(n-2) but not ending up with three consecutive negative integers. Thank you \n" ); document.write( "

Algebra.Com's Answer #766754 by ikleyn(52782) $\"\"$ $\"About$

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document.write( "The numbers are x, x+1 and x+2.\r\n" );
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document.write( "The equation is  \r\n" );
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document.write( "    (x+2) + 2x = 4*(x+1).\r\n" );
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document.write( "Simplify and find x\r\n" );
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document.write( "    x + 2 + 2x = 4x + 4\r\n" );
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document.write( "    3x         = 4x + 2\r\n" );
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document.write( "    -x = 2.\r\n" );
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document.write( "     x = -2.\r\n" );
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document.write( "The numbers are -2, -1, 0.\r\n" );
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document.write( "CNECK.  a)  0 + 2*(-2) = -4.  b)  4*(-1) = -4.\r\n" );
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document.write( "        So,  a) = b).   ! Correct !\r\n" );
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document.write( "But \"0\" is not negative, so the condition is not precisely correct.\r\n" );
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