document.write( "Question 1145488: A train leaves a station and travels north at 75km/h. Two hours later, a second train leaves on a parallel track traveling north at 125km/h. How far from the station will the second train overtake the first train?\r
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Algebra.Com's Answer #766708 by Theo(13342)![]() ![]() You can put this solution on YOUR website! r*t=d \n" ); document.write( "r = rate \n" ); document.write( "t = time \n" ); document.write( "d = distance\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "for the first train, the formula becomes 75 * t = d \n" ); document.write( "for the second train, the formula becomes 125 * (t-2) = d\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the second train will overtake the first train after they both have traveled the same distance.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since both equal to d, then both equal to each other and you get: \n" ); document.write( "75 * t = 125 * (t-2) \n" ); document.write( "simplify to get 75 * t = 125 * t - 250 \n" ); document.write( "subtract 75 * t from both sides and add 250 to both sides to get: \n" ); document.write( "250 = 125 * t - 75 * t \n" ); document.write( "combine like terms to get 250 = 50 * t \n" ); document.write( "solve for t to get t= 5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the second train will overtake the first train after they have both traveled for 5 hours.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "75 * 5 = 375 \n" ); document.write( "125 * 3 = 375\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "at exactly 5 hours, both trains will be neck and neck. \n" ); document.write( "after 5 hours, the second train will have traveled a greater distance than the first train.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |