document.write( "Question 1145488: A train leaves a station and travels north at 75km/h. Two hours later, a second train leaves on a parallel track traveling north at 125km/h. How far from the station will the second train overtake the first train?\r
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Algebra.Com's Answer #766708 by Theo(13342)\"\" \"About 
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r*t=d
\n" ); document.write( "r = rate
\n" ); document.write( "t = time
\n" ); document.write( "d = distance\r
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\n" ); document.write( "\n" ); document.write( "for the first train, the formula becomes 75 * t = d
\n" ); document.write( "for the second train, the formula becomes 125 * (t-2) = d\r
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\n" ); document.write( "\n" ); document.write( "the second train will overtake the first train after they both have traveled the same distance.\r
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\n" ); document.write( "\n" ); document.write( "since both equal to d, then both equal to each other and you get:
\n" ); document.write( "75 * t = 125 * (t-2)
\n" ); document.write( "simplify to get 75 * t = 125 * t - 250
\n" ); document.write( "subtract 75 * t from both sides and add 250 to both sides to get:
\n" ); document.write( "250 = 125 * t - 75 * t
\n" ); document.write( "combine like terms to get 250 = 50 * t
\n" ); document.write( "solve for t to get t= 5\r
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\n" ); document.write( "\n" ); document.write( "the second train will overtake the first train after they have both traveled for 5 hours.\r
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\n" ); document.write( "\n" ); document.write( "75 * 5 = 375
\n" ); document.write( "125 * 3 = 375\r
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\n" ); document.write( "\n" ); document.write( "at exactly 5 hours, both trains will be neck and neck.
\n" ); document.write( "after 5 hours, the second train will have traveled a greater distance than the first train.\r
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