document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=105323>Question 105323</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Twice the sum of two numbers is 32. Twice their difference is 4.  Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #76667 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=76667\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2(X+Y)=32<BR>\n" );
document.write( "X-Y=4 OR X=Y+4<BR>\n" );
document.write( "NOW SUBSTITUTE (Y+4) FOR X IN THE OTHERE EQUATON & SOLVE FOR Y.<BR>\n" );
document.write( "2(Y+4+Y)=32<BR>\n" );
document.write( "2(2Y+4)=32<BR>\n" );
document.write( "4Y+8=32<BR>\n" );
document.write( "4Y=32-8<BR>\n" );
document.write( "4Y=24<BR>\n" );
document.write( "Y=24/4<BR>\n" );
document.write( "Y=6 ANSWER.<BR>\n" );
document.write( "X-6=4<BR>\n" );
document.write( "X=4=6<BR>\n" );
document.write( "X=10 ANSWER.<BR>\n" );
document.write( "PROF<BR>\n" );
document.write( "2(10+6)=32<BR>\n" );
document.write( "32=32<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );