document.write( "Question 1145386: A particle moves according to the parametric equations: y=2t^2 and x=t^3 where x and y are displacements(in meters) in x and y directions respectively and t is time in seconds. Determine the acceleration after 3seconds. \n" ); document.write( "
Algebra.Com's Answer #766637 by ikleyn(52781)\"\" \"About 
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document.write( "Calculate y-component of the acceleration vector as the second derivative of \"y\" over t:   \"a%5By%5D\" = 4 m/s^2.\r\n" );
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document.write( "Calculate x-component of the acceleration vector as the second derivative of \"x\" over t and substitute t = 3 seconds:   \"a%5Bx%5D\" = 6t = 18 m/s^2.\r\n" );
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document.write( "Calculate the magnitude of the acceleration as  | a | = \"sqrt%28a%5Bx%5D%5E2+%2B+a%5By%5D%5E2%29\" = \"sqrt%284%5E2+%2B+18%5E2%29\" = \"sqrt%2816+%2B+324%29\" = \"sqrt%28340%29\" m/s^2.\r\n" );
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document.write( "Use your calculator to get the numerical value.\r\n" );
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