document.write( "Question 1145333: at a supermarket 3 oranges and 5 apples cos £2.05. at a corner store where oranges are the same but apples are 50% more expensive, 3 oranges and 5 apples cost £2.55
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Algebra.Com's Answer #766563 by ikleyn(52814)\"\" \"About 
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document.write( "Let R and A be the prices for one oRange and one Apple at the supermarket, respectively.\r\n" );
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document.write( "Then from the condition you have this system of equations\r\n" );
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document.write( "    3R +       5A = 2.05      (1)\r\n" );
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document.write( "    3R + 5*(1.5A) = 2.55      (2)\r\n" );
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document.write( "Simplify it\r\n" );
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document.write( "    3R +       5A   = 2.05    (1)\r\n" );
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document.write( "    3R +       7.5A = 2.55    (2)\r\n" );
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document.write( "To solve this system, apply the Elimination method. \r\n" );
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document.write( "For it, subtract equation (1') from (2').  You will get\r\n" );
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document.write( "               2.5A = 0.50\r\n" );
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document.write( "                  A = \"0.50%2F2.5\" = 0.2.\r\n" );
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document.write( "Then from (1),  3R + 5*0.2 = 2.05,  3R = 2.05 - 1 = 1.05,  R = 1.05/3 = 0.35.\r\n" );
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