document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1145315>Question 1145315</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Bob invested $24000. He invested part of it at 8% interest per year and the rest at 10% interest  per year. His total interest income for the year is $2300. How much was invested at 10%?\r<BR>\n" );
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document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #766547 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=766547\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "For an alternative to the traditional algebraic process for solving \"mixture\" problems like this, try this...:<br><BR>\n" );
document.write( "(1) $24000 all invested at 8% would return $1920 interest; all at 10% would return $2400 interest.<BR>\n" );
document.write( "(2) The actual interest amount, $2300, is 380/480 = 38/48 = 19/24 of the way from $1920 to $2400.<BR>\n" );
document.write( "(3) Therefore 19/24 of the money was invested at the higher rate.<br><BR>\n" );
document.write( "ANSWER: 19/24 of $24000, or $19000 at 10%; the rest at 8%.<br><BR>\n" );
document.write( "CHECK: .10(19000)+.08(5000) = 1900+400 = 2300 </SPAN>\n" );
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