document.write( "Question 1145315: Bob invested $24000. He invested part of it at 8% interest per year and the rest at 10% interest per year. His total interest income for the year is $2300. How much was invested at 10%?\r
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Algebra.Com's Answer #766536 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
a+b=24000
\n" ); document.write( "a=24000-b
\n" ); document.write( ".08*a+.10*b=2300
\n" ); document.write( "solve for b
\n" ); document.write( ".08*(24000-b)+.10*b=2300\r
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