document.write( "Question 1145289: If solution A contains 50% nitrogen and solution B contains 29% nitrogen. How much of each solution should be mixed in order to create 30 liters of a solution that contains 36% nitrogen \n" ); document.write( "
Algebra.Com's Answer #766505 by ankor@dixie-net.com(22740)\"\" \"About 
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If solution A contains 50% nitrogen and solution B contains 29% nitrogen.
\n" ); document.write( " How much of each solution should be mixed in order to create 30 liters of a solution that contains 36% nitrogen.
\n" ); document.write( ":
\n" ); document.write( "let x = amt of 50% solution
\n" ); document.write( "since the resulting amt is 30 liter:
\n" ); document.write( "(30-x) = 29% solution
\n" ); document.write( ":
\n" ); document.write( ".50x + .29(30-x) = .36(30)
\n" ); document.write( ".50x + 8.7 - .29x = 10.8
\n" ); document.write( ".50x - .29x = 10.8 - 8.7
\n" ); document.write( ".21x = 2.1
\n" ); document.write( "x = 2.1/.21
\n" ); document.write( "x = 10 liters of 50% liters nitrogen
\n" ); document.write( "then
\n" ); document.write( "30 - 10 = 20 liters of the 29% liters
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check
\n" ); document.write( ".50(10) = 5
\n" ); document.write( ".29(20) = 5.8
\n" ); document.write( "---------------
\n" ); document.write( "total = 10.8
\n" ); document.write( " \n" ); document.write( "
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