document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=105330>Question 105330</A>: <I><SPAN STYLE=\"word-break: break-all;\"> At a particular store they sell coffee for $4 a pound, cardamon for $35 a pound, and a coffee and cardamon mixture for $5 a pound.  Assuming no change in profit on selling the mix versus its components how much caradamon should be mixed with 10 pounds of coffee? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #76646 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=76646\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4*10+35*X=5(10+X)<BR>\n" );
document.write( "40+35X=50+5X<BR>\n" );
document.write( "35X-5X=50-40<BR>\n" );
document.write( "30X=10<BR>\n" );
document.write( "X=10/30<BR>\n" );
document.write( "X=1/3 POUND OF $35COMPONENTS SHOULDBE USED.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "4*10+35*(1/3)=5(10+1/3)<BR>\n" );
document.write( "40+35/3=50+5/3<BR>\n" );
document.write( "40+11 2/3=50+1 2/3<BR>\n" );
document.write( "51 2/3=51 2/3\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );