document.write( "Question 1145189: Money is borrowed at 11% simple interest. After one year, $1292.04 pays off the loan. How much was originally borrowed? \n" ); document.write( "
Algebra.Com's Answer #766403 by ikleyn(52832)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "Let x be the originally borrowed amount.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Then you have this equation for the amount after 1 year\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " x + 0.11x = 1292.04 dollars, or\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " x*(1 + 0.11) = 1292.04 dollars\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " 1.11x = 1292.04\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " x =\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Notice. In this solution, 0.11 represents 11%.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "---------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "On this subject, see the lesson\r \n" ); document.write( "\n" ); document.write( " - Simple interest percentage problems \r \n" ); document.write( "\n" ); document.write( "in this site.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |