document.write( "Question 1145189: Money is borrowed at 11​% simple interest. After one​ year, ​$1292.04 pays off the loan. How much was originally​ borrowed? \n" ); document.write( "
Algebra.Com's Answer #766403 by ikleyn(52832)\"\" \"About 
You can put this solution on YOUR website!
.
\n" ); document.write( "
\r\n" );
document.write( "Let x be the originally borrowed amount.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Then you have this equation for the amount after 1 year\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "    x + 0.11x = 1292.04  dollars,   or\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "    x*(1 + 0.11) = 1292.04 dollars\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "    1.11x        = 1292.04\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "       x         = \"1292.04%2F1.11\".\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "At this point, use your calculator/computer to find x and to get the answer.\r\n" );
document.write( "
\r
\n" ); document.write( "\n" ); document.write( "Solved.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Notice.   In this solution,  0.11 represents 11%.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "---------------\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "On this subject,  see the lesson\r
\n" ); document.write( "\n" ); document.write( "    - Simple interest percentage problems \r
\n" ); document.write( "\n" ); document.write( "in this site.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );