document.write( "Question 1145144: 4.The median life of Brand LT5 batteries is 100 hours. What is the probability that in a set of three such batteries, at least two will last longer than 100 hours? \n" ); document.write( "
Algebra.Com's Answer #766348 by ikleyn(52866)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "From the first glance,  it is clear that the given info/input is  NOT  SUFFICIENT  to solve the problem - so,  appropriate
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\n" ); document.write( "\n" ); document.write( "Moreover,  making appropriate and likelihood assumptions is the  PART of the solution.\r
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document.write( "Having nothing else given, an appropriate hypothesis is to assume that we have continuous random variable \r\n" );
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document.write( "    X = \"the time of a Brand LT5 battery service / (or \"life\")\" \r\n" );
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document.write( "with random values that are uniformly distributed with the minimum value of 0 and the maximum value of 200 hours.\r\n" );
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document.write( "Then the mean average  is exactly 100, as the problem states, and  the condition becomes \"consistent with the given part\" and \"self-closed\".\r\n" );
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document.write( "Then the probability  P(X < 100) = \"1%2F2\", as well as  P(x > 100) = \"1%2F2\".\r\n" );
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document.write( "Therefore, the probability that at least two of the three batteries will last longer than 100 hours is  \"C%5B3%5D%5E2%2A%281%2F2%29%5E3\" + \"C%5B3%5D%5E3%2A%281%2F2%29%5E3\" = \"3%2F8\" + \"1%2F8\" = \"4%2F8\" = \"1%2F2\".\r\n" );
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\n" ); document.write( "\n" ); document.write( "To see many other similar solved problems, look into the lesson\r
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\n" ); document.write( "\n" ); document.write( "In particular, this problem is VERY SIMILAR to the solved Problem 4 of that lesson.\r
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