document.write( "Question 1145118: Two rectangles A and B each have an area of 11 cm^2
\n" ); document.write( "The length of rectangle A is x cm
\n" ); document.write( "The length of rectangle B is (x+3) cm
\n" ); document.write( "Given that the width of rectangle A is 2 cm greater than the width of rectangle B form an equation in x and show that it simplifies to
\n" ); document.write( "2x^2 + 6x - 33 = 0
\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #766321 by MathTherapy(10552) $\"\"$ $\"About$

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\n" ); document.write( "Two rectangles A and B each have an area of 11 cm^2
\n" ); document.write( "The length of rectangle A is x cm
\n" ); document.write( "The length of rectangle B is (x+3) cm
\n" ); document.write( "Given that the width of rectangle A is 2 cm greater than the width of rectangle B form an equation in x and show that it simplifies to
\n" ); document.write( "2x^2 + 6x - 33 = 0
\n" ); document.write( "

With the length and area of rectangle A being x and 11, respectively, the width of rectangle A becomes: 
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document.write( "With the length and area of rectangle B being x + 3 and 11, respectively, the width of rectangle B becomes: 
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document.write( "As width of rectangle A is 2 cm GREATER than width of rectangle B, we get: 
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document.write( "11(x + 3) = 11x + 2x(x + 3) ------- Multiplying by LCD, x(x + 3)
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