document.write( "Question 1145118: Two rectangles A and B each have an area of 11 cm^2
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\n" ); document.write( "Given that the width of rectangle A is 2 cm greater than the width of rectangle B form an equation in x and show that it simplifies to
\n" ); document.write( "2x^2 + 6x - 33 = 0
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Algebra.Com's Answer #766313 by ikleyn(52781) $\"\"$ $\"About$

You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( " The solution by @josmiceli is INCORRECT.\r
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document.write( "              His equation (2) is incorrect, leading to wrong answer.\r\n" );
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document.write( "From the condition, the width of rectangle  A  is   cm.\r\n" );
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document.write( "                    the width of rectangle  B  is  cm.\r\n" );
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document.write( "Also, from the condition\r\n" );
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document.write( "     -  = 2  cm.      (1)\r\n" );
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document.write( "It is your basic equation, and at this point, the setup is just completed.\r\n" );
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document.write( "Now my (and your) major task is to transform this equation to the standard form of a quadratic equation.\r\n" );
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document.write( "For it, multiply both side of the equation (1) by  x*(x+3).  You will get\r\n" );
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document.write( "    11*(x+3) - 11x = 2x*(x+3)\r\n" );
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document.write( "    11x + 33 - 11x = 2x^2 + 6x\r\n" );
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document.write( "    2x^2 + 6x - 33 = 0.\r\n" );
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document.write( "Your question is answered:  The equation in your post IS CORRECT.      ANSWER\r\n" );
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