document.write( "Question 1145075: A rectangular piece of metal is 25in longer than it is wide. Squares with sides
\n" ); document.write( "5 in long are cut from the four corners and the flaps are folded upward to form an open box. If the volume of the box is 930 in^3, what were the original dimensions of the piece of​ metal?
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Algebra.Com's Answer #766257 by josgarithmetic(39616)\"\" \"About 
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Open Box dimensions:
\n" ); document.write( "height, 5 inches
\n" ); document.write( "length, w+25-2*5=w+15
\n" ); document.write( "width, w-10
\n" ); document.write( "volume, 930 cubic inches\r
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\n" ); document.write( "\n" ); document.write( "\"5%28w%2B15%29%28w-10%29=930\"
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