document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1144982>Question 1144982</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi<BR>\n" );
document.write( "Tom traveled for 2 hours at 10mph then stopped for 1 hour then continued to travel at the same speed.Gerald started his travel along the same route 3.75 hours laterthan tom at 32mph.<BR>\n" );
document.write( "how far from the starting point will gerald be when he catches up with tom.\r<BR>\n" );
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document.write( "thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #766174 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=766174\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Since Gerald started 3.75 hours after Tom, and since Tom rested during one of those hours, the distance between them when Gerald starts is 2.75(10) = 27.5 miles.<br><BR>\n" );
document.write( "The difference in their speeds is 32-10 = 22mph.<br><BR>\n" );
document.write( "The time required for Gerald to catch up with Tom is the difference in the distances, divided by the difference in the speeds: 27.5/22 = 1.25 hours.<br><BR>\n" );
document.write( "Gerald traveling as 32mph for 1.25 hours will travel 32(1.25) = 40 miles.<br><BR>\n" );
document.write( "ANSWER: Gerald will catch up with Tom 40 miles from the starting point.<br><BR>\n" );
document.write( "CHECK: When Gerald has traveled for 1.25 hours, Tom has traveled 2.75+1.25 = 4 hours; 4 hours at 10mph equals 40 miles. </SPAN>\n" );
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