document.write( "Question 1144982: Hi
\n" );
document.write( "Tom traveled for 2 hours at 10mph then stopped for 1 hour then continued to travel at the same speed.Gerald started his travel along the same route 3.75 hours laterthan tom at 32mph.
\n" );
document.write( "how far from the starting point will gerald be when he catches up with tom.\r
\n" );
document.write( "\n" );
document.write( "thanks \n" );
document.write( "
Algebra.Com's Answer #766167 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! Tom traveled for 2 hours at 10 mph then stopped for 1 hour then continued to travel at the same speed. Gerald started his travel along the same route 3.75 hours later than Tom at 32 mph.\r \n" ); document.write( "\n" ); document.write( "How far from the starting point will Gerald be when he catches up with Tom?\r \n" ); document.write( "\n" ); document.write( "In the first 2 hours, Tom went 20 miles \n" ); document.write( "The next hour he rested \n" ); document.write( "3.75-3=.75 hr. \n" ); document.write( "Then he went .75 *10=7.50 miles\r \n" ); document.write( "\n" ); document.write( "Tom had a headstart of 27.5 mi. \n" ); document.write( "10x+27.5=32x \n" ); document.write( "27.5=22x \n" ); document.write( "x=1.25 hrs\r \n" ); document.write( "\n" ); document.write( "32*1.25=40 \n" ); document.write( "They met at the 40 mi marker \n" ); document.write( "check \n" ); document.write( "1.25*10=12.5 mi \n" ); document.write( "27.5+12.5.=40 \n" ); document.write( " |