document.write( "Question 1144914: The doubling time of an investment with continuous compound interest is 12.6 years. If the investment is worth ​$20,000 ​today, how much will it be worth 5 years from​ now?\r
\n" ); document.write( "\n" ); document.write( "It will be worth ​$_
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Algebra.Com's Answer #766116 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
the formula for continuous compounding is f = p * e ^ (r * n).
\n" ); document.write( "the doubling time is given as 12.6 years.
\n" ); document.write( "formula becomes 2 = 1 * e ^ (r * 12.6)
\n" ); document.write( "simplify to:
\n" ); document.write( "2 = e ^ (r * 12.6)
\n" ); document.write( "take the natural log of both sides of this equation to get:
\n" ); document.write( "ln(2) = ln(e ^ (r * 12.6))
\n" ); document.write( "by logarithmic rules, this becomes:
\n" ); document.write( "ln(2) = r * 12.6 * ln(e) which becomes ln(2) = r * 12.6
\n" ); document.write( "solve for r to get r = ln(2) / 12.6 = .055011681\r
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\n" ); document.write( "\n" ); document.write( "confirm by replacing r in the original equaton with that to get:
\n" ); document.write( "2 = e ^ (.055011681 * 12.6)
\n" ); document.write( "e ^ (.055011681 * 12.6) = 2, confirming the continuous compounding interest rate is correct.\r
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\n" ); document.write( "\n" ); document.write( "that interest rate remain the same, regardless of the number of years, so.....
\n" ); document.write( "f = 20,000 * e ^ (.055011681 * 5) = 26,332.15138.
\n" ); document.write( "that's your solution.\r
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\n" ); document.write( "\n" ); document.write( "graphically, the continuoous compounding equation looks like this.\r
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\n" ); document.write( "\n" ); document.write( "as you can see from the graph, the doubling time is every 12.6 years.
\n" ); document.write( "it went from 20,000 to 40,000 in 12.6 years and then to 80,000 in another 12.6 years.\r
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