document.write( "Question 1144909: A model rocket is launched with an initial upward velocity of 151 ft/s. The rockets height “h” (in feet) after “t” seconds is given by the following. H=151t-16t squared.
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document.write( "Find the values of “t” for which the rockets height is 88 feet.
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document.write( "Round your answer to the nearest hundredth. \n" );
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Algebra.Com's Answer #766095 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! 151t -15t^2 = 88 \n" ); document.write( ": \n" ); document.write( "-15t^2 +151t -88 = 0 \n" ); document.write( ": \n" ); document.write( "the rocket follows the path of a parabola that curves downward, quadratic formula is \n" ); document.write( ": \n" ); document.write( "t = (-b + or -square root(b^2 -4ac))/2a \n" ); document.write( ": \n" ); document.write( "therefore there two solutions for t \n" ); document.write( ": \n" ); document.write( "t = (-151 +square root(151^2 -4 * -15 * -88))/(2*-15) = 0.62 seconds \n" ); document.write( ": \n" ); document.write( "t = (-151 -square root(151^2 -4 * -15 * -88))/(2*-15) = 9.45 seconds \n" ); document.write( ": \n" ); document.write( " |