document.write( "Question 1144896: 3,4,9,7,1,3,4,9,7,1,3...
\n" ); document.write( "in the sequence above, the numbers 3,4,9,7 and 1 repeat in that order, starting with 3. Whatcis the 43rd term of the sequence?
\n" ); document.write( "A)6
\n" ); document.write( "B)7
\n" ); document.write( "C)8
\n" ); document.write( "D)9
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Algebra.Com's Answer #766091 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "The repeating sequence is 5 numbers. Terms 5, 10, ..., 35, and 40 will all be the last number in the sequence, 1. Then 3 more terms to get to the 43rd term puts you at 9.

\n" ); document.write( "ANSWER D

\n" ); document.write( "Shortcut: 43/5 = 8 remainder 3, so the 43rd term is the same as the 3rd term: 9
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