document.write( "Question 1144894: Arnold sets out for a hike. After walking for some time, he discovers that he left his lunch. A passing passenger bus takes him back home at 40kph. When he gets home he finds out that he was gone for 1 hour. How far did he walk if his rate was 5 kph?
\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #766083 by ikleyn(52776) $\"\"$ $\"About$

You can put this solution on YOUR website!
.
\n" ); document.write( "

\r\n" );
document.write( "\r\n" );
document.write( "Let \"d\" be the unknown distance.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Then you have this \"time\" equation\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "     +  = 1 hour.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "To solve it, multiply both sides by 40. You will get\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "    8d + d = 40,\r\n" );
document.write( "\r\n" );
document.write( "    9d = 40\r\n" );
document.write( "\r\n" );
document.write( "     d =  kilometers.    ANSWER\r\n" );
document.write( "

\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "==================\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "I am solving, printing and posting faster (and in more correct way) than you copy, paste and submit (!)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "I won (!)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );