document.write( "Question 1144878: Hazel and emilie fly from city A to city B. The flight from A to B is against the wind and takes 2 hrs. The return flight with the wind takes 1.5hrs. If the wind speed is 44mph, find the speed of the plane in still air.
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Algebra.Com's Answer #766067 by ikleyn(52797) $\"\"$ $\"About$

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document.write( "Let x be the speed of the plane at no wind (the unknown value under the question).\r\n" );
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document.write( "Then from the condition, we have this equation\r\n" );
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document.write( "    2(x - 44) = 1.5*(x + 44).\r\n" );
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document.write( "It says that the distance is the same in both directions.\r\n" );
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document.write( "Simplify and solve for x\r\n" );
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document.write( "    2x - 88 = 1.5x + 66\r\n" );
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document.write( "    2x - 1.5x = 66 + 88\r\n" );
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document.write( "    0.5x = 154\r\n" );
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document.write( "       x =  = 308.\r\n" );
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document.write( "ANSWER.  The speed of the plane in still air is 308 miles per hour.\r\n" );
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