document.write( "Question 1144827: Letter A substitutes a nonzero digit and AA is a two-digit number. The product of AA and A is always.
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document.write( "F) even
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document.write( "G)divisible by 3
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document.write( "H)divisible by 11
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document.write( "J) a perfect square \n" );
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Algebra.Com's Answer #766015 by Edwin McCravy(20059)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "\"AA\" where A is both the tens and units digit.\r\n" ); document.write( "t=A, u=A\r\n" ); document.write( "The value 10t+u becomes 10A+A which is 11A,\r\n" ); document.write( "which is always divisible by 11.\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |