document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=105258>Question 105258</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0073268623/algebrahomeworkh>University of Phoenix Elementary and Intermediate Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Ok my favorite tutors, I only have 2 more questions, at least until monday:) You guys rock!!!\r<BR>\n" );
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document.write( "Ziggy's famous yogurt blends regular yogurt that is 3% fat with its no-fat yogurt to obtain low-fat yogurt that is 1% fat.  How many pounds of regular yogurt and how many pounds of no-fat yogurt should be mixed to obtain 60 pounds of low-fat yogurt?\r<BR>\n" );
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document.write( "Can you please help me set this up and solve it??? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #76601 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=76601\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=required amount of yogurt that is 3% fat <BR>\n" );
document.write( "Then 60-x=required amount of no-fat yogurt \r<BR>\n" );
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document.write( "Now we know that the amount of pure fat in the 3% yogurt (0.03x) plus the amount of pure fat in the no-fat yogurt (0) has to equal the amount of pure fat in the final 1% yogurt mixture(0.01*60) so or equation to solve is:\r<BR>\n" );
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document.write( "0.03x=0.01*60 simplify\r<BR>\n" );
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document.write( "0.03x=0.6  divide both sides by 0.03<BR>\n" );
document.write( "x=20 lbs-----------------------------amount of yogurt that is 3% fat\r<BR>\n" );
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document.write( "60-x=60-20=40 lb-------------------------amount of no-fat yogurt needed\r<BR>\n" );
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document.write( "CK\r<BR>\n" );
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document.write( "0.03*20=0.01*60<BR>\n" );
document.write( "0.6=0.6\r<BR>\n" );
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document.write( "Hope this helps---ptaylor </SPAN>\n" );
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