document.write( "Question 1144836: One number is five less than another. The sum of their squares is 97. Find the numbers. \n" ); document.write( "

Algebra.Com's Answer #766003 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let the numbers be:
\n" ); document.write( " $\"+x+-+5+\"$
\n" ); document.write( " $\"+x+\"$
\n" ); document.write( "---------------
\n" ); document.write( " $\"+x%5E2+%2B+%28+x-5+%29%5E2+=+97+\"$
\n" ); document.write( " $\"+x%5E2+%2B+x%5E2+-+10x+%2B+25+=+97+\"$
\n" ); document.write( " $\"+2x%5E2+-+10x+-+72+=+0+\"$
\n" ); document.write( " $\"+x%5E2+-+5x+-+36+=+0+\"$
\n" ); document.write( " $\"+%28+x+-+9+%29%2A%28+x+%2B+4+%29+=+0+\"$ ( by looking at it )
\n" ); document.write( " $\"+x+=+9+\"$
\n" ); document.write( " $\"+x+-+5+=+4+\"$
\n" ); document.write( "( I will use the positive result )
\n" ); document.write( "The numbers are 9 and 4
\n" ); document.write( "-----------------------------------
\n" ); document.write( "check:
\n" ); document.write( " $\"+x%5E2+%2B+%28+x-5+%29%5E2+=+97+\"$
\n" ); document.write( " $\"+9%5E2+%2B+%28+9-5+%29%5E2+=+97+\"$
\n" ); document.write( " $\"+81+%2B+16+=+97+\"$
\n" ); document.write( " $\"+97+=+97+\"$
\n" ); document.write( "OK
\n" ); document.write( "---------------------------
\n" ); document.write( "The negative answers also work:
\n" ); document.write( " $\"+x+%2B+4+=+0+\"$
\n" ); document.write( " $\"+x+=+-4+\"$
\n" ); document.write( "and
\n" ); document.write( " $\"+x+-+5+=+-9+\"$
\n" ); document.write( "The numbers are -4 and -9
\n" ); document.write( "--------------------------------\r
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