document.write( "Question 14990: can you please tell me what does this mean: 17-( x3)=5
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document.write( "i have to figure out what =5 from taking 17 away from 3x something \n" );
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Algebra.Com's Answer #7659 by hyh_124(6)![]() ![]() ![]() You can put this solution on YOUR website! Dont get worried its pretty simple. \n" ); document.write( "first analyse the situation \n" ); document.write( "the question is 17-(x3)=5 \n" ); document.write( "multiply x3 by '-' \n" ); document.write( "you will have -3x\r \n" ); document.write( "\n" ); document.write( "now solve\r \n" ); document.write( "\n" ); document.write( "17-3x=5 (shift 17 to the other side)\r \n" ); document.write( "\n" ); document.write( "-3x =5-17 \n" ); document.write( "-3x =-12 (take minus common) \n" ); document.write( " 3x =12 \n" ); document.write( " x =12/3 \n" ); document.write( " x =4\r \n" ); document.write( "\n" ); document.write( "Check \n" ); document.write( "17-3x =5 \n" ); document.write( "17-3(4)=5 \n" ); document.write( "17-12 =5 \n" ); document.write( " 5 =5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |