document.write( "Question 1144639: A farmer planted a trial poppy crop in a rectangular plot 40 metres long and 35 metres wide. The trial was successful, so the next year the farmer decides to increase the poppy plot by a further 1000 square metres. To do this the farmer increases the width of the plot by x metres and the length of the plot by 4x metres.
\n" ); document.write( "a) Draw a diagram with the following information
\n" ); document.write( "b) What is the total area (in m^2) of the larger poppy plot?
\n" ); document.write( "c) Write an equation, in standard quadratic form, to describe the area of the larger poppy plot in terms of x.
\n" ); document.write( "d) Using your equation in part c), apply algebraic techniques to find the dimensions (length and width) of the larger poppy plot.
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Algebra.Com's Answer #765840 by greenestamps(13203)\"\" \"About 
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\n" ); document.write( "(a) You can draw the diagram....

\n" ); document.write( "(b) (40*35)+1000 = 1400+1000 = 2400

\n" ); document.write( "(c) (40+4x)(35+x) = 2400

\n" ); document.write( "(d)
\n" ); document.write( "\"%2840%2B4x%29%2835%2Bx%29+=+2400\" original equation
\n" ); document.write( "\"%2810%2Bx%29%2835%2Bx%29+=+600\" factor out the common factor of 4 from the first expression to keep the numbers smaller
\n" ); document.write( "\"x%5E2%2B45x%2B350+=+600\"
\n" ); document.write( "\"x%5E2%2B45x-250+=+0\"
\n" ); document.write( "\"%28x%2B50%29%28x-5%29+=+0\"
\n" ); document.write( "\"x+=+-50\" or \"x+=+5\"

\n" ); document.write( "Clearly the -50 makes no sense in the problem; so x=5.

\n" ); document.write( "The dimensions of the large field are
\n" ); document.write( "length: 40+4(5) = 60
\n" ); document.write( "width: 35+5 = 40
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